![]() |
![]() |
#1 |
Helper EcoRenovator
Join Date: Dec 2010
Location: US
Posts: 57
Thanks: 1
Thanked 17 Times in 11 Posts
|
![]() Another interesting energy storage idea.
![]() https://www.wired.com/2016/05/forget...ed-train-hill/ https://vimeo.com/39364772 https://vimeo.com/75895781?from=outro-embed https://vimeo.com/48546631?from=outro-embed > |
![]() |
![]() |
The Following User Says Thank You to redneck For This Useful Post: | stevehull (05-18-16) |
![]() |
#2 |
Steve Hull
Join Date: Dec 2012
Location: hilly, tree covered Arcadia, OK USA
Posts: 826
Thanks: 241
Thanked 165 Times in 123 Posts
|
![]() Redneck - how about figuring out how much energy you would get from 2000 kg (car weight) going down a 100 foot (33 meter) hill?
Steve
__________________
consulting on geothermal heating/cooling & rational energy use since 1990 |
![]() |
![]() |
![]() |
#3 |
Helper EcoRenovator
Join Date: Dec 2010
Location: US
Posts: 57
Thanks: 1
Thanked 17 Times in 11 Posts
|
![]() |
![]() |
![]() |
![]() |
#4 |
Apprentice EcoRenovator
Join Date: Aug 2012
Location: North Alabama
Posts: 167
Thanks: 0
Thanked 40 Times in 20 Posts
|
![]() P.E. = m X g x h
m = 2000 kg, g = 9.81 m/s^2, h = 33 m P.E. = 647460 J Assuming it takes the car 60 seconds to travel down the hill and there is 100% conversion: P = E/T P = 10.791 kW Assuming 50% conversion (after friction and conversion losses), you are looking at 5 kW. |
![]() |
![]() |
![]() |
|
|