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TechShop · 11-19-15, 11:26 AM

I measured an LG brand 5K unit I have here in the shop.
It has 2 parallel circuits of approximately 19 feet of copper that measures .215" OD.

Since that tubing is smaller, I would do the following math to match the internal volume using 1/4" copper:

area of .215" OD copper = .1075^2 * pi = .03631
area of .250" OD copper = .1250^2 * pi = .04909

ratio of volume will be = .03631 / .04909 = .7397 or 73.97%

So due to it's larger diameter, I only need 73.97% of the length if I'm using the larger size 1/4" copper tubing.

19' (per circuit) * .7397 = 14.05' (per circuit).

That means a 28 foot total length of copper cut into two circuits. In my mind I could justify whacking that down to by 1.5' per circuit to use a 25 foot coil. By my math, I would suggest you make two 12' circuits out of a 25 foot coil and stick with the existing cap tube.

Of course, you should probably check those measurements against your condenser and also use the ID of the copper, not the OD.

11-19-15, 11:26 AM	#3
TechShop FNG Join Date: Jul 2015 Location: Washington Posts: 71 Thanks: 8 Thanked 19 Times in 13 Posts	I measured an LG brand 5K unit I have here in the shop. It has 2 parallel circuits of approximately 19 feet of copper that measures .215" OD. Since that tubing is smaller, I would do the following math to match the internal volume using 1/4" copper: area of .215" OD copper = .1075^2 * pi = .03631 area of .250" OD copper = .1250^2 * pi = .04909 ratio of volume will be = .03631 / .04909 = .7397 or 73.97% So due to it's larger diameter, I only need 73.97% of the length if I'm using the larger size 1/4" copper tubing. 19' (per circuit) * .7397 = 14.05' (per circuit). That means a 28 foot total length of copper cut into two circuits. In my mind I could justify whacking that down to by 1.5' per circuit to use a 25 foot coil. By my math, I would suggest you make two 12' circuits out of a 25 foot coil and stick with the existing cap tube. Of course, you should probably check those measurements against your condenser and also use the ID of the copper, not the OD.